How to calculate your Helium miner’s transmit scale | Everything about HIP17 hex and reward scales

you might have suffered that your hotspotis alone in your hex but the compensation flake or the give scale is still less than one orthe configuration around your hotspot has not changed at all but your remuneration knowledge still wentdown and you are wondering why that happened in this video we will have an in-depth discussionon how turn magnitude or the give flake is calculated along with a detailed understandingof hexes at different resolutions hey folks this is roy and welcome back to my channel eigentechyou might think that if you are alone in your hex at settlement 8 your reward magnitude of thetransmit flake is always “re going to be” 1 but “thats really not” actually true-life tell us check afew problematic precedents so here i am showing you a hex where there existed one hotspot as youcan see here and there are no hotspots around this hex the only outspots are prettyfar so this the reward scale for this one should have been one but you can seeit’s not one it’s instead 0.69 so what’s wrong here another example is i am showing youhere let me turn on the move magnitude now um so you can see there by the cluster ofhot spots now these sixes have only single hot spots inside it and these three have two hotspots inside it so you can see that for this and this hex uh the channel magnitude is one but for someunknown reason this the hot spots in this hex have only 0.5 which should have shouldn’t have been thecase it should have your scale of one so why is it so so in the first part of this video i’ll giveyou a quick answer of how the give abilities are calculated and what could be the problems and thesecond part i will give you a more detailed answer for the quick answer we will go tothe browser and type and once it lades we can click on this searchicon here and nature the figure of your hotspot in this case we’ll check this problematic hotspot andi have already laden its information and then you go to the reward scaling invoice now and that willshow you uh some details about the remunerations of this particular hotspot so this is the net or totalreward proportion which is 0.69 so let us now check the breakdown of the honor scale after differentresolutions so you might once know that uh to compute the remuneration flake the numberof hotspots at different resolutions are used in particular starting from resolution 10 all the way up to resolution 4. So in this case you can see that the calculated wage flake fordifferent solutions are principally penalty starting from resolution 10 all the way up to resolutionfive but the problematic hex is solving four and there are 363 too many hotspots they aresupposed to be uh so 800 would have been the optimal number of hot spots and because there are3 63 more smudges your scale is 0.69 you can check that so the numeral is basically 800 divided among 800 plus 363 which is 1163 and that gives you 0.68787 so it’s 0.69 nearly so too uh this app isnice it goes to show uh in ruby-red hue the spotlit below which one is the problematic hex and youcan see for the other cases successfully occupied fully occupied which is fine which means that thenumber of hot spot in that resolution is equal to the optimal number of hot spots and then thereare four more available at resolution seven twenty four ever available six and so on and uh on thetop of this sheet in the map it shows you the this colored hex shows you the problematic results okayso in this case nothing can be done because uh the problem is at much larger scale so there is nohope for this one i am showing you another example here where the reverse scale is only 0.15 verybad and in the disintegration you can see there are troubles at various magnitude starting from resolution1 0 place 8 7 and 5 but what is important here resolve 10 intends it’s really tiny spaceand if you click on here you will see that as mostly the two hotspots are very close toeach other and if one moves it somewhat apart the region adjusts the place either this one moves hereobviously moves now ah the reverse scale for this particular um hex which is resolution 10 will goto one and to then to compute the final resolving what you have to do that you have to simplymultiply uh to get the final or net wage scale or channel scale you have to multiplyuh that your proportion at all different solvings that will give you the final reward ability and ahthe other problematic one which one as this one so luxurious jet black zebra i have also loadedit now and you can see that the problem is only at resolution 10 which represents two hotspots are really really close to each other you can see in this map it’s very close soin this case the simple solution is to move uh one of these hotspots slightly away sofor example let’s say this one to ah x a at settlement 10 and that will solve the problem andyou don’t need to even physically move it because this is a very close distance uh you can always seta spot which is within 50 to 100 meters of the actual physical location and that should still befine in terms of earning or witnessing each other i hope you now understand how to estimate thetotal reward skill given the reward skill at individual resolutions and you will be also ableto perform diagnosis at which resolve the problem exists if your compensation magnitude is not one ifthe problem happens at a very high resolution like solution 10 or settlement 9 hex then there is achance to fix it by reasserting the orientation but if it happens at a much broader resolution likeresolution four or five ah there is not much hope because it ah involves a much much larger areaand you cannot change the site of other hotspots of course all right tell us now move tothe second part of this video where we will have an in-depth discussion on how to really computethe move science for that first we need to have a good understanding of the hexagons at differentresolutions in this presentation i am showing you hexagons at different resolutions starting fromresolution 11 all the way up to resolution 4. So higher the number symbolizes the finer it is so thesmaller the area and a smaller resolution entails a larger area so if you talk about the weapon lengthit starts from 30 rhythm for settlement 11 for this resolution 10 66 meter and it goes all the way upto 22.6 rhythm six kilometer for settlement four if you take the fraction between any uh consecutiveuh hex for example 66 rhythm by 30 meter uh between uh basically forearm period otherwise 10 hex dividedby s11 hex is going to be 62.646 and it’s going to be the same if you take the proportions of 1.22 kilometer divided among 461 kilometer so basically this is the ratio of any two consecutivepairs so settlement rx divided by resolution r plus 1 x so this was the limb segment if you look atthe area which is more interesting so uh domain of resolution 10 x divided by resolution 11 x isgoing to be 7 and again it’s going to be same for any two consecutive point so what does thisseven number mean it actually has a physical make so if we considered uh hexes as a at resolutioneight and seven these are not up to scale uh and tell us proceed seven resolve eights whichare neighboring in this fashion then you can see that the resolution 7x will look like this soseven solving eight hexes are enclosed inside one resolving seven hex okay and in this case itwill call that resolution seven is the parent hex and settlement eight is the child hex okay and ifyou now consider seven uh resolve seven hexes as shown by this green hexagons here then theparent solving six hexagon will look like this and this is true for any any resolution so onehex at settlement r will be equal to seven hex at resolution r in terms of area okay we can have abetter understanding of the hexagon rotting by looking at a interactive delineate for that wewill go to the browser and kind helium dot residence then we will turn on the resolution 8 hex bytoggling this button here close it and then zoom in to any place “youd prefer” and let it laden andthen i’ll click on some distinguish now and you can see that now this uh red zone is the bad zone whereyou should not have any other hotspot if there is a hotspot at the centre for human rights and this black hexagonsare the resolution eight hexagon okay then let me now start here and turn on resolution nine as welland now you can see that inside one answer eight hex there are seven solution nine hexessimilarly as i told you it’s true for any um for any resolution hexes so i will turn this off andturn the resolution 7 on and then if you zoom out a little bit you can see now that inside aresolution 7 hex there are 7 resolve 8 hexes so the outside hex will be called the parentheticand the inside axis will be called the child hex now this might look a little bit confusing becauseyou can see that some part of this resolution eight hex is outside the parent hex okay butto see a more clearer picture we can go back to the hot spotty page earlier i registered you thisresolution 10 hexagon now we can go back and let’s scroll down here and click on resolution eight hexand it will now show you the proper bound it looks like a kind of a bloom determine okay so thisis how the actual uh this is the actual shape of the hex that is actually used in the calculationsbut for the purpose of this video we’ll keep it simple and use regular hexagons as i demonstrated youin the presentation so the next important pitch is to understand the number of hot spots thatis optimal for a demonstrated answer because that is the number which defines your individualreward abilities so there are some default amounts which is uh so resolution 11 is not considereduh star merely resistance starting party 10 is considered and the default number of hotspots is one and one for outlook nine and then it increases gradually and goes to 250 for resolutionfour okay so i call this list in time which you can think as the maximum number of miners uh thatcan be present in a contributed hex before the give magnitude is reduced below one so if your hotspotnumber for example let’s say at seven outdoes six uh the transmit proportion all of all of them uh willgo down and it will become five divided by six but this number is actually not static it’sdynamic and that introduces in the intricacy uh so the end clip value actually increases fromthis default value to a peak cost uh it increases gradually and under certain conditionsare met and the maximum values are still it’s one for resolution 10 for 9 it’s 2 4 20 and forresolution 4 it’s 800 okay in the later part of this video we’ll discuss how this n time numberincreases from default value to this maximum value and under what kind of conditions so tell us nowtake the default values now and try to compute the channel flake for a held hotspot okay so ihave grayed out the rules and regulations 11 and it is not being used and then this is showing you then clip numbers which are the default values so here i have prepared a table and showingyou the clip multitude the same numbers are here for different solutions okay and this next rowis showing you the number of members of miners at different resolution hexes so at uh from starting from 10 up to resolution eight there are only one miner so mostly if you have a minor in any childx you’ll always have that minor in in in its planet x okay so in answer seven there areeight eight minus 20 90 now and 300 okay so the formula to calculate transmit scale at individualhexes is given by this so hex transmit scale is minimum of either 1 or n divided by n minus sowhat it means that you have to divide in clip this quantity by n child and if this numeral is smallerthan 1 then you use that multitude but if this count is larger than one “youre using” one now one importantpoint to remember is that the n adolescent is defined as the number of interactive miners theinteractive miners means those hot spot which has which have locale said and haveuh whose beacon signals have been witnessed by other horsepower in other words its lighthouse signalshould have a valid weakness right okay so those are the interactive hotspots and non-interactivehotspots are have always zero remuneration flake so um so we can simplify this math expressionand simply compute the ratio between n time and n minor so if it’s greater than one you say trueif it’s less than one it will you say it incorrect in other words if the number of minor present in hexis smaller or equal to the number of uh optimal number of hot spots it’s true or green and if it’smore than that it’s false so if it’s true uh you can consider that the move proportion is simplyone for that particular hex but when it’s untrue you have to take the fraction so in this case fivedivided by 8 which is 0.625 and now 250 divided by 300 which is 0.833 and then to compute the netor total transmit scale we have to really multiply all these numbers together since 1 doesn’t matterwe just proliferate 6 to 5 with 833 and that gives you 0.521 that would be the reverse scale ofthis particular minor with this configuration now if you just simply let’s say somebodyelse contributes another hotspot at decide eight okay so it was earlier only your hotspot butanother hotspot uh comes at solution eight so then you have to add one hotspot for uh allthe resolutions up to so from eight all the way up to four and then since in this case this alsobecomes false likewise you have to take the rate between n time and n child now which is0. 5 and other numbers slightly get amended and now the total transmit scale will be themultiplication of an expression of the results of these three causes and that becomes 0.231 so you cansee that it reformed drastically earlier it was 0.5 and now it became 0.23 it’s just not afactor of 2 is more than a factor of 2 in this case so you can see the compensation magnitude went downmainly because there was the limitation was only one hotspot at settlement 8 hex before the reversescale is clipped however this crowd in clip can change as i told you earlier this is a dynamicnumber so in this next area we are trying to try to understand how that happens and when thathappens and in that case you have to likewise consider its neighbor so in this picture i am showing youseven solution eight hexes constituted by blue and then uh this is the hex under considerationwhere we are going to target our hotspot and these are there its neighbors and the dashedline in violet goes to show the resolution seven hex and notice that the neighbors can be placedin a different parent leaders okay um so the parentheses for this resolution eight hex is thisone the bottom one but these ones have a different mother so since there are no hot spots around theend clip is set to its default value which is one so if i now place one hotspot in this hex youryour knowledge shown by color is going to be 1.0 however if i target two hot spot that is somewhatoptimal and that is why the diversification is going to going to go down by risk factors of 2 and becomes willbecome 0.5 inside this hex for this particular hex but this can change depending on the number ofsaturated neighboring hex so i am just calling exactly employing a period saturated hex which basicallymeans how many neighbours are there which have n minor or the number of children in that x largerthan or equal to n excerpt which is the default value which is one here in this case so uh here is atable which goes to show that that what should be this enabled value after which the end clip can beupgraded and it has different figure for different decide so we are considering resolution eightso that is why i have highlighted it in bold so it has to be two in this case so right now a neighboris zero because there is no hot spots around it so which is less than in saturation so the endclip is still going to be one now i place another one in its neighbor so that overturn proportion is goingto be 1.0 however since in neighbor is one which is less than in saturation in clip is still goingto be one so this reward scale doesn’t improve now i place another hotspot in at its neighbor andthe neighbor now n neighbour is similar to two which is equal to the n saturation okay and uh so thesenumbers are on chain variable counts which i have are caught up from f17 um information and nowthis nk time can be upgraded because it quenches this condition it becomes now 2 and thus this yourscale no longer need to be 0.5 but it becomes 1.0 okay so now i can further increase it so ifi place another hotspot in another neighbor so now end neighbor is three so in clip can alsobe three so you can place three hotspots inside settlement eight hex without the payoff scalebeing uh fetch down okay you add another it becomes four but can it keep increasing can youplace like six neighbours and can this become six no because there is again a limitation on thiswhich is uh constituted by this n max list and again it is different for different resolutionsfor answer eight this is four okay but that meant that even if i place um five hot spot inthis neighbor the maximum number of hot spots that i can target now without the reverse skill beinggone down being fetch down is still going to be four so with four hot spots you can still haveyour scale of one uh also in this scenario the situation for other other access also improve forexample for this hotspot you have two neighbors with a two neighbors with having more than onehot spot so it can have now at maximum of two hot spot with a alter flake of 1.0 similarly thishex has three neighbors and so that this can have three hotspots inside it similarly this one threethis one three and this one two okay if you now increase another hotspot here since mission excerpt hasbeen maxed out it’s still for your ability is going to go down the factor will be 4 divided by 5which is 0.8 uh so if you arrange for example 6 hotspots here it will be 3 divided by 6 whichis 0.5 and again if i increase the number of members of hotspots in this hex to 10 because the numberof granted what recognize was simply two it the reverse scale for each of the hotspots becomes pointtwo and so note that uh these is these multitudes are obtained by considering there are no otherhotspots around it and then finally this was the these are the transmission scales for thisparticular resolution which is resolution eight but to get the final or net disseminate flake youhave to take the product of transmission skills and at all resolutions as i established you earlierso and even though i registered you this particular example for resolution 8 the same explanationholds for all the dispensations but the figure in saturation and in max will be differentand these are the chain variable counts okay another important interpretation of this table isthat under no circumstances a hotspot can have a turn science equivalent to 1 if the total number ofhot spots in that hex becomes larger than this in max number for example if you considerresolution 6 hex if the full amounts of the number of hot spots in that resolution hex becomes greater than 100 all hotspots inside that hex including its child hexes the payoff magnitude is going to be smaller thanone okay now i will answer a few commonly asked questions the first one is what is a good rewardskill in this table i have partitioned the honor or move flake in 5 different categories anythingbetween 0.95 and 1 would be excellent between 0.75 to 0.95 would be good mediocre would be 0.5 to0. 75 0.25 to 0.5 0 is 4 and anything below 0.25 is terrible okay so you’d like to be in the rangeyou’d like to have a reverse scale in the range of 0.75 to 1. The second question is how does thereward scale affect your ironing so actually the wage proportion of your hotspot doesn’t affect yourironing instantly it instead alters the ironing of other hotspots in your vicinity so basicallywhenever you send a beacon signal and it is received by other hotspots as a legitimate witnessthe earning will be scaled down by the factor of your give scale nonetheless it can affectyour earnings indirectly so tell us check that uh so here is a seven hexes atresolution settlement eight and this is the distribution of hot spot since thereare two neighboring hotspots have the saturated are saturated the end clip for this hex is goingto be two and there could be two hotspots with a reverse magnitude of one so if these hotspots sendsa become signal and received by this hotspot then with a valid with this let’s say it can make pointone agent okay um this is because the reverse scale is one it will not be scaled down similarlyuh another witness by this hotspot will likewise pay stage 1 hnt nonetheless let’s say these twohotspots are pretty close to each other let’s say within settlement 10 then you know that theyour proportion is going to go down to 0.5 as i demo you earlier in the presentation and in that casewhat will happen that the beacon signal sent by this hotspot will be received by this but itwill become an invalid witness because saying that it’s too close to each other or most likelythe rssi value is too high so you can see that the reverse skill has indirectly affecting yourearning because you are you can no longer earn from this hotspot so it’s saying that that inthat case that your science is saying that there are other hot spots in your environ and one needs tomove those around to either you have to move your satan or the other beings have to move theirsand also in this case this hotspot also pays less hmd i could have earned point one earlier butsimply because that locating declaration this one will make now 0.05 negotiator and that is how you cansee that the turning of the neighboring hotspots is effect but you can still lose weaknessesand that is how you can lose your earnings and the third question is how regularly is thisreward skill updated it can it can get updated whenever a brand-new hotspot arrived at the your hex so itcould be any uh starting from resolution 10 to all the way up to resolution four so if a new hotspotscomes or the locale is assigned inside that hex the reverse skill might be updated similarly ifa hotspot loses or advantages its interactive status as i asked earlier either your knowledge can getmodified as well and you can expect that you are skill changing a few times a day i hope with thisinformation you will be now able to understand how the payoff magnitude is calculated and then alsoperform diagnosis at what resolution position the problem exists if your resolve if your reversescale is less than one and again to reiterate if the problem or the reverse scale is small atthe higher settlement like resolving 10 or settlement 9 you can most likely fix it by simplyreasserting its spot uh if it happens if the problem exists at a much larger resolution likeresolution four five or six you cannot really do anything because it because it uh involves so manyhot spots in a very large widespread area i hope this information was useful to you and clarifysome of your suspenses if you have any more question let me know in the comment section that’s all fortoday thanks for watching people and get kryptonized

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